合并分支 'master' 到 'mengxia'

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Chapter1/chapter1.tex

@@ -274,7 +274,7 @@
 %----------------------------------------------
 \begin{figure}[htp]
     \centering
-\input{./Chapter1/Figures/four-levels-of-rbmt}
+\input{./Chapter1/Figures/figure-four-levels-of-rbmt}
     \caption{基于规则的机器翻译方法的四个层次\upcite{冯志伟2004机器翻译研究}}
 \setlength{\belowcaptionskip}{-1.5em}
     \label{fig:1-10}
@@ -292,7 +292,7 @@
 %----------------------------------------------
 \begin{figure}[htp]
     \centering
-\input{./Chapter1/Figures/process-of-rule-based-translation}
+\input{./Chapter1/Figures/figure-process-of-rule-based-translation}
     \caption{基于转换规则的机器翻译过程}
     \label{fig:1-11}
 \end{figure}
@@ -303,7 +303,7 @@
 %----------------------------------------------
 \begin{figure}[htp]
     \centering
-\input{./Chapter1/Figures/example-of-source-structure}
+\input{./Chapter1/Figures/figure-example-of-source-structure}
     \caption{一个汉语句子的结构表示（句法树）}
     \label{fig:1-12}
 \end{figure}
@@ -324,7 +324,7 @@
 %----------------------------------------------
 \begin{figure}[htp]
     \centering
-\input{./Chapter1/Figures/comparison-between-interlingua-based-and-transfer-based-translation}
+\input{./Chapter1/Figures/figure-comparison-between-interlingua-based-and-transfer-based-translation}
     \caption{基于中间语言的方法(a)与基于转换的方法(b)}
     \label{fig:1-13}
 \end{figure}

Chapter10/Figures/figure-query-model-corresponding-to-attention-mechanism.tex

@@ -23,7 +23,7 @@
 \draw [->] ([yshift=1pt,xshift=-3pt]query.north) .. controls +(90:2.5em) and +(90:2.5em) .. ([yshift=1pt]key4.north);
 \node [anchor=south east] (alpha1) at ([xshift=1em]key1.north east) {\scriptsize{$\alpha_1=.4$}};
 \node [anchor=south east] (alpha2) at ([xshift=1em]key2.north east) {\scriptsize{$\alpha_2=.4$}};
-\node [anchor=south east] (alpha3) at ([xshift=1em]key3.north east) {\scriptsize{$\alpha_3=0$}};
+\node [anchor=south east] (alpha3) at ([xshift=1em]key3.north east) {\scriptsize{$\alpha_3=.1$}};
 \node [anchor=south east] (alpha4) at ([xshift=1em]key4.north east) {\scriptsize{$\alpha_4=.1$}};
 
 \end{scope}